1Z1-071 EXAM REVIEW - QUESTIONS 1Z1-071 EXAM

1z1-071 Exam Review - Questions 1z1-071 Exam

1z1-071 Exam Review - Questions 1z1-071 Exam

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Oracle 1z0-071 Certification Exam is designed to test the skills of candidates in various areas such as SQL fundamentals, data retrieval using SQL, data manipulation, and database design. 1z1-071 exam comprises multiple-choice questions and requires candidates to have a thorough understanding of SQL concepts and Oracle Database management. 1z1-071 exam is based on the latest version of Oracle Database, which makes it highly relevant for current industry needs.

Oracle 1z0-071 certification exam is a computer-based test that consists of 73 multiple-choice questions. 1z1-071 Exam has a duration of 105 minutes, and the passing score is 63%. 1z1-071 exam fee is $245, and candidates can register for the exam through the Oracle Certification website. To prepare for the exam, candidates can take advantage of various training resources, including online courses, practice exams, and study guides. Passing the Oracle 1z0-071 certification exam is an excellent way to validate your SQL programming skills and enhance your career opportunities in the database industry.

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Oracle 1z1-071 certification exam covers a wide range of topics related to Oracle Database SQL. These topics include SQL fundamentals, database design, data manipulation, and data control. 1z1-071 exam also covers topics such as subqueries, joins, set operators, and data aggregation. By passing 1z1-071 Exam, individuals will have demonstrated their ability to work with Oracle Database SQL in a variety of contexts.

Oracle Database SQL Sample Questions (Q121-Q126):

NEW QUESTION # 121
Which two queries execute successfully?

  • A. SELKCT COALESCE (100, 'A') FROM DUAL;
  • B. SELECT NULLIF (100, 'A') FROM DUAL;
  • C. SELECT NULLIF(NULL, 100) FROM DUAL;
  • D. SELECT NULLIF (100) FROM DUAL;
  • E. SELECT COALESCE(100, NULL, 200) FROM DUAL;

Answer: D,E


NEW QUESTION # 122
Which two statements will return the names of the three employees with the lowest salaries?

  • A. SELECT last_ name, salary
    FROM employees
    WHERE ROWNUM <=3
    ORDER BY salary
  • B. SELECT last_ name, salary
    FROM
    (SELECT" FROM employees ORDER BY salary)
    WHERE ROWNUM <=3
  • C. SELECT last name, salary
    FROM employees
    ORDER BY salary
    FETCE FIRST 3 RONS ONLY;
  • D. SELECT last_ name, salary
    FBOM employees
    WEERE
    ORDER BY SELECT
    ROINUM <= 3
    salary FROM
    employees);
  • E. SELECT last_ name, salary
    FROM employees
    FETCH FIRST 3 ROWS ONLY
    ORDER BY salary;

Answer: B,E

Explanation:
A: This statement is correct. It orders the employees by salary and fetches the first 3 rows.
B: This statement has a typo with "FETCE" and "RONS" which should be "FETCH" and "ROWS". Hence, it will not execute successfully.
C: This statement will not execute successfully due to syntactical errors and incorrect use of the ORDER BY clause.
D: This statement is correct. It uses a subquery to order employees by salary and then limits the results to the first 3 using the ROWNUM pseudo-column.
E: This statement will not execute successfully because ROWNUM is evaluated before the ORDER BY clause, so it would return the first 3 rows based on the table's natural order, not the lowest salaries.
The behavior of ROWNUM and the FETCH FIRST syntax are explained in the Oracle Database SQL Language Reference 12c.


NEW QUESTION # 123
Examine this description of the PRODUCTStable:

Rows exist in this table with data in all the columns. You put the PRODUCTStable in read-only mode.
Which three commands execute successfully on PRODUCTS? (Choose three.)

  • A. DROP TABLE products;
  • B. ALTER TABLE products DROP UNUSED COLUMNS;
  • C. TRUNCATE TABLE products;
  • D. ALTER TABLE products DROP COLUMN expiry_date;
  • E. CREATE INDEX price_idx ON products (price);
  • F. ALTER TABLE products SET UNUSED (expiry_date);

Answer: A,C,E


NEW QUESTION # 124
The CUSTOMERStable has a CUST_LAST_NAMEcolumn of data type VARCHAR2.
The table has two rows whose CUST_LAST_NAMEvalues are Anderson and Ausson.
Which query produces output for CUST_LAST_NAMEcontaining Oder for the first row and Aus for the second?

  • A. customers;
    SELECT REPLACE (SUBSTR(cust_last_name, -3), 'An', 'O') FROM customers;
  • B. customers;
    SELECT INITCAP (REPLACE(TRIM('son' FROM cust_last_name), 'An', 'O')) FROM
  • C. SELECT REPLACE (TRIM(TRAILING 'son' FROM cust_last_name), 'An', 'O') FROM
  • D. SELECT REPLACE (REPLACE(cust_last_name, 'son', ''), 'An', 'O') FROM customers;

Answer: D


NEW QUESTION # 125
Which two statements will convert the string Hello world to ello wozid?

  • A. SELECT LOWER (SUBSTR('Hello World', 2)) FROM DUAL;
  • B. SELECT LOWER (SUBSTR('Hello World, 2, 1)) FROM DUAL;
  • C. SELECT LOWER(TRIM('H' FROM 'Hello World')) FROM DUAL;
  • D. SELECT SUBSTR('Hello world', 2) FROM DUAL;
  • E. SELECT INITCAP(TRIM('H' FROM 'Hello World')) FROM DUAL;

Answer: A,D

Explanation:
To convert the string "Hello World" to "ello wozid":
Option B: SELECT LOWER(SUBSTR('Hello World', 2)) FROM DUAL;
This will remove the first character and convert the rest to lowercase, but it will not change the 'rld' to 'zid'.
Option D: SELECT SUBSTR('Hello world', 2) FROM DUAL;
This will remove the first character, but the rest of the string remains unchanged and not converted to lowercase.
Options A, C, and E are incorrect because:
Option A: SUBSTR is incorrect here because it is only getting one character instead of the entire string minus the first character.
Option C: While TRIM removes the 'H', LOWER converts all characters to lowercase, but it doesn't address the 'rld' to 'zid' change.
Option E: INITCAP and TRIM will not achieve the desired conversion of 'rld' to 'zid'.


NEW QUESTION # 126
......

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